r/HomeworkHelp • u/Fine_Two_923 • 10h ago
High School Math—Pending OP Reply [Math-70 Elementary/Highschool Algebra: Graphically solving a system of linear equations] Do I make the 4 into a -4 ?
Hey so this might seem like a silly question but I want to know if you have a -x = 4 if it turns into a -4. I have the other parts of the graphing completed it’s just this part that I don’t want to make a mistake on!!! Thank you in advance
P.S- the reason it’s says elementary/highschool math is because I am taking a beginner math class not a algebra class In elementary
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u/Temporary_Pie2733 10h ago
Where are you getting -x in the first place? x - 0 = 4 simplifies directly to x = 4.
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u/Plane_Tailor7168 10h ago
yes thats what i was comfused about lol
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u/Wooden-Hornet2115 9h ago
What I'm confused about is OP saying they have a system of linear equations, when they only have one equation.
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u/Plane_Tailor7168 10h ago
it should just be x=4
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u/Broad-Raspberry-6296 10h ago
You’re right. He made a mistake from 2nd to 3rd line. x-0=4 is x=4 lol
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u/Wooden-Hornet2115 9h ago
Are you trying to fimd the X-intercept? You don't have a system of equations, you have an equation.
Also, yes if -x = 4, x = -4. In this specific equation, x = 4. I don't know how you got -x = 4.
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u/slayyerr3058 10h ago
In -x = 4, there is an invisible negative one as the coefficient on the x. Divide both sides by negative one to remove it.
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u/Plane_Tailor7168 10h ago
i think you missunderstood him (or im just an idiot)
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u/Plane_Tailor7168 10h ago
wait no im sorry but i think he messed up in the image bc it should just be x=4
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u/Serafim91 9h ago
"-x" is actually "+(-1)*x". The -1 is the same as any other coefficient and can be multiplied and divided as needed following the same rules.
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u/wijwijwij 9h ago
If you are seeking an x-intercept of the graph of x – 4y = 0 you can put 0 for y and solve for x. Your first two lines look good.
But x - 0 is not –x. It is just x. So your third line should be x = 4, meaning (4, 0) is on the graph.
By the way, if order was switched, 0 - x would be –x. Is that maybe what you were thinking when writing third line?
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u/CalRPCV 9h ago
As has been pointed out, a system of equations involves more than one equation. What you have written is confusing and could have a few different interpretations. I could make up a system of equations from it:
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x - 4y = 4
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-x = 4
In other words, these are two separate equations, not one derived from the other. If that is the case, then equation 1 would be a line with a slope of 1/4 that intersected the x axis at 4 because x - 4(0) = 4 means when y is zero, x is 4. The slope of the line can be seen on your graph. Or you can re-arrange the equation as y = (1/4)x - 1. The y intercept, where x is 0, is -1.
Then equation 2 is a vertical line crossing the x axis at - 4.
If you drew the graph for each equation then they would intersect at the point (-4, -2).
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u/CalculadoraAlicia-ap 2h ago
Both parts are true, and keeping them separate helps:
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The general rule: if you ever do get -x = 4, then yes, x = -4. Think of -x as (-1) times x, so divide (or multiply) both sides by -1: (-1)(-x) = (-1)(4), which gives x = -4.
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In this specific work, though, you do not have -x. Starting from x - 4y = 4 and setting y = 0 for the x-intercept: x - 4(0) = 4, so x - 0 = 4, so x = 4. That gives the point (4, 0) on the graph. The minus sign belongs to the 4y term, not to x, so it disappears when y = 0.
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u/Broad-Raspberry-6296 10h ago
Think of it as multiplying -1 to both sides of the equation. So yes, -x * (-1) = 4 * (-1) will give you x=-4
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u/Plane_Tailor7168 10h ago
i think you missunderstood him (or im just an idiot)
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u/Plane_Tailor7168 10h ago
wait no im sorry but i think he messed up in the image bc it should just be x=4
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